Core practical 4: the initial rate of enzyme-catalysed reactions

Membranes, Proteins, DNA and Gene Expression · Proteins and enzymes · note 6 of 6

Core practical 4: the initial rate of enzyme-catalysed reactionsSpec 2.8

In short

In core practical 4, you change one factor (temperature, pH, enzyme concentration or substrate concentration) and measure the initial rate of an enzyme-catalysed reaction, for example the volume of oxygen produced by catalase. The initial rate is found from the gradient of the tangent at time zero on a graph of product against time.

Core practical:

Core practical 4: investigate the effect of temperature, pH, enzyme concentration and substrate concentration on the initial rate of enzyme-catalysed reactions.

A suitable system is catalase breaking down hydrogen peroxide into water and oxygen. The oxygen is collected, and the volume is measured over time. (Other systems also work, for example amylase and starch, where the time for the iodine colour to disappear is measured, or the breakdown of milk protein by a protease.)

  1. Place a fixed volume of hydrogen peroxide solution, adjusted to the chosen pH with a buffer, in a boiling tube and bring it to the chosen temperature in a water bath.
  2. Add a fixed volume of catalase solution (for example from yeast or liver) and immediately connect a delivery tube to a gas syringe or an upturned measuring cylinder over water.
  3. Start a stopwatch. Record the volume of oxygen at regular intervals (for example every 10 seconds) for several minutes.
  4. Repeat at least three times for each value of the independent variable, and calculate a mean.
Variables for each version of the investigation
Independent variableHow to change itKeep constant
TemperatureWater baths at, for example, 10, 20, 30, 40, 50 and 60 °C.pH (buffer), enzyme concentration and volume, substrate concentration and volume.
pHBuffer solutions of different pH, for example pH 3 to 10.Temperature, enzyme and substrate concentrations and volumes.
Enzyme concentrationDilute the enzyme stock to give a range of concentrations (serial dilution).Temperature, pH, substrate concentration and volume.
Substrate concentrationDilute hydrogen peroxide stock to a range of concentrations.Temperature, pH, enzyme concentration and volume.

Risk management

  • Hydrogen peroxide is an irritant (and stronger solutions are corrosive): wear eye protection and gloves, and wash splashes off skin.
  • Do not use a very high concentration of enzyme with high hydrogen peroxide, because the gas is evolved quickly: use a gas syringe or a measuring cylinder that is big enough.
  • Hot water baths can scald.

Finding the initial rate

Plot the volume of product (y axis) against time (x axis). The curve is steepest at the start, then levels off as substrate is used up. Draw a tangent to the curve at time zero, and calculate its gradient. The gradient is the initial rate.

initial rate = change in volume of product ÷ change in time (gradient of the tangent at t = 0)

Initial rate from a graph

A tangent drawn to the curve at time zero passes through the points (0 s, 0 cm³) and (20 s, 14 cm³). Calculate the initial rate of the reaction.

  1. Initial rate = change in volume ÷ change in time.
  2. = (14 − 0) cm³ ÷ (20 − 0) s.
  3. = 0.70 cm³ s⁻¹.

Answer: 0.70 cm³ s⁻¹ (the unit is cm³ per second).

Maths skill:

Use a large triangle on the tangent to find the gradient. If the rate is taken from a data table instead, use the first, steepest interval. Give the unit (for example cm³ s⁻¹ or mm³ min⁻¹). Percentage change is also used to compare rates between treatments: (new − original) ÷ original × 100.

Exam tip:

In an evaluation, enzymes at different temperatures must be brought to temperature before they are mixed. Otherwise the reaction starts at the wrong temperature and the initial rate is not valid.

Core practical 4 apparatus of a boiling tube containing hydrogen peroxide and catalase in a water bath with a thermometer and a gas syringe, and a graph of volume of oxygen against time with a tangent at t = 0 and a right-angled triangle showing change in volume and change in time. (opens full size in a new tab)
Core practical 4: find the initial rate from the gradient of a tangent at t = 0. Illustrative graph.

Quick check

  1. Name the bond that links two amino acids.

    Show answer

    A peptide bond (covalent), formed in a condensation reaction that releases water.

  2. Which bonds hold the tertiary structure of a protein?

    Show answer

    Hydrogen bonds, ionic bonds and disulfide bonds (plus hydrophobic interactions).

  3. Why is haemoglobin soluble?

    Show answer

    Hydrophilic R groups face outwards, so it dissolves in the cytoplasm of red blood cells.

  4. What does an enzyme do to the activation energy of a reaction?

    Show answer

    It lowers it.

  5. How is the initial rate of reaction found from a graph?

    Show answer

    From the gradient of the tangent drawn at time zero on a graph of product against time.

Written and checked against the Edexcel International AS Level Biology (XBI11) specification · Updated October 2026

Frequently asked questions

What is the difference between primary, secondary, tertiary and quaternary protein structure?

Primary structure is the sequence of amino acids joined by peptide bonds. Secondary is coiling into an alpha helix or folding into a beta pleated sheet, held by hydrogen bonds. Tertiary is the overall 3D folding, held by hydrogen, ionic and disulfide bonds. Quaternary is two or more polypeptides together.

How are the structures of haemoglobin and collagen related to their functions?

Haemoglobin is globular and soluble, with four polypeptides each holding an iron-containing haem group that binds oxygen. Collagen is fibrous and insoluble: three polypeptides form a triple helix with hydrogen bonds and cross-links, giving great tensile strength for support in tendons and skin.

Why do enzymes denature at high temperatures?

High temperatures give the enzyme molecule more kinetic energy, which breaks the hydrogen and ionic bonds holding the tertiary structure. The active site changes shape, so the substrate can no longer fit, and the enzyme-substrate complex cannot form. This denaturation is not reversible.

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