Protein synthesis: exam questions

5 questions, 15 marks. Write your answers on paper, then open each mark scheme.

Question 1

Paper 1A style

During transcription, which base on the RNA strand pairs with adenine on the DNA template strand?

  1. Thymine
  2. Uracil
  3. Guanine
  4. Cytosine
[1 mark]
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Answer: B ;

Question 2

Paper 1A style

The codons GAA and GAG both code for glutamic acid. Which feature of the genetic code does this show?

  1. Universality
  2. It is a triplet code
  3. Degeneracy
  4. It is non-overlapping
[1 mark]
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Answer: C ;

Question 3

Paper 1B style

The table shows part of the mRNA codon table. A short section of mRNA has the sequence AUG UUU CAU GAG UGG UAA. (a) Deduce the sequence of amino acids coded by this mRNA. [2] (b) Deduce the base sequence of the DNA template strand for the first two codons. [1] (c) A mutation changes the fourth codon from GAG to GUG. Using the table, state the effect on the polypeptide and suggest how this could affect the protein's function. [2]

Part of the mRNA codon table
CodonAmino acid
AUGMet (start)
UUUPhe
CAUHis
GAGGlu
GUGVal
UGGTrp
UAAstop
[5 marks]
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  • (a) Met – Phe – His – Glu – Trp;
  • (a) translation ends at UAA / stop codon (no amino acid added); Award [1] for four correct amino acids in order
  • (b) TAC AAA; Accept 3'-TAC AAA-5' or 5'-AAA CAT-3'
  • (c) glutamic acid replaced by valine (at that position) / one amino acid changed;
  • (c) different R group / hydrophobic instead of charged, so the polypeptide folds differently / changes shape;
  • (c) protein may lose function / function altered, e.g. as in haemoglobin S; OWTTE
  • max 5

Question 4

Paper 2A style

Explain why the genetic code must be a triplet code.

[2 marks]
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  • there are 20 (types of) amino acids (to be coded for) and 4 bases;
  • a doublet code gives only 4² = 16 combinations, which is not enough;
  • a triplet code gives 4³ = 64 combinations, which is enough (with some to spare for start/stop or degeneracy);
  • max 2

Question 5

Paper 2B style

Describe how a polypeptide is elongated during translation.

[6 marks]
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  • mRNA binds to the small subunit of the ribosome;
  • mRNA is read in codons / triplets of bases;
  • tRNA carries a specific amino acid;
  • tRNA anticodon pairs with the complementary codon on mRNA;
  • by hydrogen bonding / complementary base pairing (A–U, C–G);
  • two tRNAs bind (to the large subunit) at the same time;
  • a peptide bond forms between the amino acid and the growing polypeptide;
  • the polypeptide is transferred to the (amino acid on the) second tRNA;
  • the ribosome moves along the mRNA by one codon;
  • the first tRNA (without an amino acid) is released;
  • process repeats, adding one amino acid at a time in the order set by the codons;
  • max 6